In genetic studies on malaria, the A allele represents a 'normal' variant and the S allele represents a 'blood disorder' varient. Which of these genotypes confers protection against malaria while allowing an individual to survive the blood disorder and reproduce? Answers: AS None of these genotypes will confer protection SS AA
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Hardy-Weinberg problem (12 pts) The A allele is normal for hemoglobin and is dominant. The S allele is a mutation that arose, causing sickle cell disease. The AA genotype is susceptible to malaria, which is caused by the protist Plasmodium. The heterozygote and homozygote recessive individuals are protected against malaria. Individuals who are homozygous recessive in the population develop sickle cell disease, which is frequently fatal. Children are most susceptible to malaria, and life is shortened in those who have sickle cell disease. This is all the information that was included for this question on the worksheet.
Suman K.
Sri K.
Sickle-cell anemia is an interesting human genetic disease. Normal homozygous individuals (SS) have normal blood cells that are easily infected with the malarial parasite. Many of these individuals become very ill from the parasite and many die. Individuals homozygous for the sickle-cell trait (ss) have red blood cells where malaria cannot grow; however, their red blood cells readily collapse when deoxygenated and these individuals often die because of this genetic defect. Individuals with the heterozygous condition (Ss) have some sickling of red blood cells, but generally not enough to cause mortality. However, malaria cannot survive well within these "partially defective" red blood cells. Thus, heterozygotes tend to survive better than either of the homozygous conditions. If 16% of an African population is born with a severe form of sickle-cell anemia (ss), predict what percentage of the population will be more resistant to malaria because they are heterozygous (Ss) for the sickle-cell gene.
Bryan V.
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