In hobbits hairy feet h are dominant to smooth feet h and...

In hobbits hairy feet (H) Are dominant to smooth feet (h) And big ears (B) Dominant too small ears (b). You cross true breeding hobbits with Harry feet and small ears with true breeding hobbits with smooth feet and big ears. The resulting heterozygous offspring are then crossed with true breeding hobbits that have smooth feet and small ears, Producing 100 total hobbit babies. How many of each phenotype do you expect to see if the genes are unlinked? Report your answers as a whole number and double check that they add to give you 100 total offspring -hairy feet, big ears -hairy feet, small ears -smooth feet, big ears -smooth feet, small ears How many of each phenotype do you expect to see if the two jeans are located 12 math units apart on the same chromosome report your answers as whole numbers and double check that they add to give you 100 total offspring -hairy feet, big ears -hairy feet, small ears -smooth feet, big ears -smooth feet, small ears

Transcript

00:01 Okay, this question here says, how it fit can be hairy or smooth.

00:04 Hairy is dominant over smooth.

00:06 So in this case, let's use the h.

00:08 So when you have the homozygous dominant for h or agitator, you're going to get hairy fit.

00:15 And the homozygous is going to be for smooth fit.

00:20 Now it says, for another characteristic, their personality can be gorgeous or timid.

00:26 So in this case, let's use the c.

00:28 Or let's use the e.

00:33 So the homozygous dominant or the heterozygous is gonna code for courageous while the homozygous aggressive is gonna code for timid like i said, a true breeding hairy means homozygous so you have true breeding hairy and true breeding courageous means like this east cross with a true breeding smooth and timid it means like this so from this cross all the opposite are gonna be heterozygous for both traits because this parent can only give dominant alleles and this parent can only give recessive alleles then he says what is the genotype or infinitum ratios of the f1 hobbits so in this case the genotype ratio is going to be when you have two genes you're going to get a total of 16 possibilities in all of these 16 possibilities all of them are going to be like this so the genotype ratio is going to be 16 to 0 because all of them are going to be like this heterocycle for both genes and the phenotype is going to be also 16 to 0 because all of the offspring are going to have this genotype that calls for the phenotype that is hairy and courageous.

01:48 Now it says one of the f1 hobbits mates with another hobbit of the of the same genotype so you have this cross and it says without using a panel square it is possible to predict the phenotype ratio of their offspring what is the ratio so when you have a type hybrid cross the phenotype ratio ratio is going to be 9, 3, 3, and 1.

02:17 Okay.

02:18 So this is going to be the ratio of all of the offspring here.

02:24 So, for example, the gametes produced by this parent are going to be this, this, this, and this.

02:34 Okay...

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