In one experiment, 4.1 g AgNO3 and 3.5 g of NaCl produced 2.44g of AgCl. What was the percentage yield of AgCl?
Added by Julia V.
Step 1
For this, we need to know the balanced chemical equation for the reaction. The balanced equation is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that one mole of AgNO3 reacts with one mole of NaCl to produce one mole of AgCl. Show more…
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