Question

In the following exercises, use direct substitution to show that each limit leads to the indeterminate form 0$/ 0$ . Then, evaluate the limit. $$\lim _{x \rightarrow 9} \frac{t-9}{\sqrt{t}-3}$$

Name: in the following exercises use direct substitution to show that each limit leads to the indeterminate form 0 0 then evaluate the limit lim x rightarrow 9 fract 9sqrtt 3 3
Uploaded: 2021-08-26T00:59:35-08:00
Duration: 1 min 29 s
Channel: Suman Saurav Thakur
Description: in the following exercises use direct substitution to show that each limit leads to the indeterminate form 0 0 then evaluate the limit lim x rightarrow 9 fract 9sqrtt 3 3

          In the following exercises, use direct substitution to show that each limit leads to the indeterminate form 0$/ 0$ . Then, evaluate the limit.
$$\lim _{x \rightarrow 9} \frac{t-9}{\sqrt{t}-3}$$

Added by Patrick C.

Calculus Volume 1

Gilbert Strang 1st Edition

Chapter 2

Instant Answer

Solved by Expert Suman Saurav Thakur

08/26/2021

Step 1

$$\lim _{t \rightarrow 9} \frac{t-9}{\sqrt{t}-3} = \frac{9-9}{\sqrt{9}-3}$$ Show more…

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In the following exercises, use direct substitution to show that each limit leads to the indeterminate form 0$/ 0$ . Then, evaluate the limit. $$\lim _{x \rightarrow 9} \frac{t-9}{\sqrt{t}-3}$$