00:01
Hello guys, when this question we have been given, the mass of phthalic acid, so mt is equal to 5 grams.
00:07
Volume of methanol is given that is equal to 5 ml.
00:10
Density of methanol is equal to 0 .7 -91 gram per ml.
00:20
Also, the mass of methanol given is 3 .96 grams.
00:25
So we have to find the limiting reagent first, limiting reactant.
00:30
So now we have this reaction of pterothelic acid and methanol.
00:36
Reaction is this is the acid plus methanol will be two moles of ch3 oh so it will give us esterification this acid it will become cooch3 on both the coh and there are two moles of h2o so now one mole of ferralic acid reacts with two modes of methanol to give one mole of ester and two moles of h2o so now the mass given are so the molecule masses are 166, 64, 194 and 36 grams.
01:22
So this is the molecular mass and 64 gram of methanol required requires 166 gram of theratholic acid.
01:29
So 1 gram will require 166 divided by 64 and 3 .96 grams will require 166 divided by 64 but we have 5 gram of pteraphylic acid.
01:50
So this is the required mass of pteraphylic acid but we only have 5 grams available.
01:58
So from this we can tell that our limiting reagent will be limiting reagent is theraphylic acid.
02:14
So this is the final answer of the first part of the question...