Question

$$\int x\sqrt{x+1}dx$$ Integralinde $$t = \sqrt{x+1}$$ dönüşümü yapılırsa aşağıdaki Integrallerden hangisi oluşur? O a. $$\int t(t^2-1)dt$$ O b. $$2\int t^2(t^2-1)dt$$ O c. $$\int (t^2-1)dt$$ O d. $$\frac{1}{2}\int (t^2-1)dt$$

Name: int xsqrtx1dx integralinde t sqrtx1 donusumu yaplrsa asagdaki integrallerden hangisi olusur o a int tt2 1dt o b 2int t2t2 1dt o c int t2 1dt o d frac12int t2 1dt 96377
Uploaded: 2021-09-20T14:51:36-08:00
Duration: 6 min 2 s
Channel: Kumareshwaran Rathinasabapathy
Description: int xsqrtx1dx integralinde t sqrtx1 donusumu yaplrsa asagdaki integrallerden hangisi olusur o a int tt2 1dt o b 2int t2t2 1dt o c int t2 1dt o d frac12int t2 1dt 96377

          $$\int x\sqrt{x+1}dx$$
Integralinde $$t = \sqrt{x+1}$$ dönüşümü yapılırsa aşağıdaki
Integrallerden hangisi oluşur?

O a. $$\int t(t^2-1)dt$$
O b. $$2\int t^2(t^2-1)dt$$
O c. $$\int (t^2-1)dt$$
O d. $$\frac{1}{2}\int (t^2-1)dt$$

$int xsqrtx1dx integralinde t sqrtx1 donusumu yaplrsa asagdaki integrallerden hangisi olusur o a int tt2 1dt o b 2int t2t2 1dt o c int t2 1dt o d frac12int t2 1dt 96377$

Added by Tyler M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kumareshwaran Rathinasabapathy

09/20/2021

Step 1

We are given the substitution $$t = \sqrt{x+1}$$. Step 2: From the substitution $$t = \sqrt{x+1}$$, we can square both sides to get $$t^2 = x+1$$. From this, we can express $$x$$ in terms of $$t$$: $$x = t^2 - 1$$. Step 3: Next, we need to find $$dx$$ in terms Show more…

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$$\int x\sqrt{x+1}dx$$ Integralinde $$t = \sqrt{x+1}$$ dönüşümü yapılırsa aşağıdaki Integrallerden hangisi oluşur? O a. $$\int t(t^2-1)dt$$ O b. $$2\int t^2(t^2-1)dt$$ O c. $$\int (t^2-1)dt$$ O d. $$\frac{1}{2}\int (t^2-1)dt$$