Question

4. \int_0^3 \frac{x^2}{\sqrt{1+x}}dx is equal to a) \frac{24}{5} b) \frac{74}{15} c) \frac{76}{15} d) \frac{26}{5} e) \frac{16}{3}

          4. \int_0^3 \frac{x^2}{\sqrt{1+x}}dx is equal to

a) \frac{24}{5}
b) \frac{74}{15}
c) \frac{76}{15}
d) \frac{26}{5}
e) \frac{16}{3}

4. ∫0^3 (x^2)/(√(1+x))dx is equal to

a) (24)/(5)
b) (74)/(15)
c) (76)/(15)
d) (26)/(5)
e) (16)/(3)

Added by Javier C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

05/09/2022

Step 1

Let's substitute u = 1 + x, then du = dx. Show more…

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int_0^3 (x^(2))/(sqrt(1+x))dx is equal to a) (24)/(5) b) (74)/(15) c) (76)/(15) d) (26)/(5) e) (16)/(3) Y 4 dx is equal to 0 V1+x 24 74 5 5 76 5 26 5 16 3

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Question

4. \int_0^3 \frac{x^2}{\sqrt{1+x}}dx is equal to a) \frac{24}{5} b) \frac{74}{15} c) \frac{76}{15} d) \frac{26}{5} e) \frac{16}{3}

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