Question

24. $\int_1^3 (x^3 + 5x^2) dx$, $R_n = \frac{2}{n} \sum_{i=1}^n \left[ 6 + \frac{26i}{n} + \frac{32i^2}{n^2} + \frac{8i^3}{n^3} \right]$

Name: 24. ∫1^3 (x^3 + 5x^2) dx, Rn = (2)/(n)∑i=1^n [ 6 + (26i)/(n) + (32i^2)/(n^2) + (8i^3)/(n^3)]
Uploaded: 2022-01-08T08:37:19-08:00
Duration: 2 min 51 s
Channel: Shubham Kanungo
Description: 24. ∫1^3 (x^3 + 5x^2) dx, Rn = (2)/(n)∑i=1^n [ 6 + (26i)/(n) + (32i^2)/(n^2) + (8i^3)/(n^3)]

          24. $\int_1^3 (x^3 + 5x^2) dx$, $R_n = \frac{2}{n} \sum_{i=1}^n \left[ 6 + \frac{26i}{n} + \frac{32i^2}{n^2} + \frac{8i^3}{n^3} \right]$

Added by Lawrence S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Shubham Kanungo

01/08/2022

Step 1

∫(x^3 + 5x^2)dx = (1/4)x^4 + (5/3)x^3 | from 1 to 3 = (1/4)(3^4) + (5/3)(3^3) - (1/4)(1^4) - (5/3)(1^3) = (81/4) + (135/3) - (1/4) - (5/3) = 20.25 + 45 - 0.25 - 1.67 = 63.33 Show more…

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