Integral of square root(1 + (x-3)) dx from 3 to 6
Added by Christopher B.
Step 1
We need to evaluate the integral \(\int_{3}^{6} \sqrt{1 + (x - 3)} \, dx\). We can simplify the expression inside the square root: \[ 1 + (x - 3) = x - 2. \] Thus, the integral becomes: \[ \int_{3}^{6} \sqrt{x - 2} \, dx. \] Show more…
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