integral of x^2+2x+4 / (x^2-1)
Added by Kenny C.
Step 1
Step 1:** Simplify the given function by factoring the denominator: \[ \frac{x^2 + 2x + 4}{x^2 - 1} = \frac{4}{x^2 - 1} = \frac{2 + 2}{x^2 - 1} = \frac{2(x + 1)}{(x + 1)(x - 1)} = \frac{2}{x - 1} \] ** Show more…
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