Question

lim_{x ofrac{pi}{2}^{-}}tan^{-1}(e^{tanx})=

          lim_{x	ofrac{pi}{2}^{-}}tan^{-1}(e^{tanx})=

$limx ofracpi2^-tan^-1(e^tanx)=$

Added by Gregg M.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Yujie Wang

02/08/2023

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