Question

1. An NPN BJT with base-emitter and base-collector junction areas $A_{JE}$ and $A_{JC}$, respectively, has the following parameters: the transport factor $\alpha_T = 0.9999$ and the emitter efficiency $\gamma_E = 0.9968$. The ratings of the transistor are as follows: the maximum collector current $I_{max}$ is 10 mA, and the maximum collector-base voltage $V_{max}$ is 25V. What would the BJT parameters and ratings be if both junction areas ($A_{JE}$ and $A_{JC}$) are doubled? (a) $\beta = 604$, $I_{max} = 10$ A, $V_{max} = 25$ V (b) $\beta = 302$, $I_{max} = 20$ mA, $V_{max} = 25$ V (c) $\beta = 604$, $I_{max} = 20$ mA, $V_{max} = 50$ V (d) $\beta = 151$, $I_{max} = 10$ mA, $V_{max} = 25$ V (e) $\beta = 302$, $I_{max} = 20$ mA, $V_{max} = 12.5$ V (f) $\beta = 604$, $I_{max} = 20$ mA, $V_{max} = 25$ V

          1. An NPN BJT with base-emitter and base-collector junction areas $A_{JE}$ and $A_{JC}$,
respectively, has the following parameters: the transport factor $\alpha_T = 0.9999$ and the
emitter efficiency $\gamma_E = 0.9968$. The ratings of the transistor are as follows: the
maximum collector current $I_{max}$ is 10 mA, and the maximum collector-base voltage
$V_{max}$ is 25V. What would the BJT parameters and ratings be if both junction areas ($A_{JE}$
and $A_{JC}$) are doubled?
(a) $\beta = 604$, $I_{max} = 10$ A, $V_{max} = 25$ V
(b) $\beta = 302$, $I_{max} = 20$ mA, $V_{max} = 25$ V
(c) $\beta = 604$, $I_{max} = 20$ mA, $V_{max} = 50$ V
(d) $\beta = 151$, $I_{max} = 10$ mA, $V_{max} = 25$ V
(e) $\beta = 302$, $I_{max} = 20$ mA, $V_{max} = 12.5$ V
(f) $\beta = 604$, $I_{max} = 20$ mA, $V_{max} = 25$ V
        
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1. An NPN BJT with base-emitter and base-collector junction areas AJE and AJC,
respectively, has the following parameters: the transport factor = 0.9999 and the
emitter efficiency = 0.9968. The ratings of the transistor are as follows: the
maximum collector current Imax is 10 mA, and the maximum collector-base voltage
Vmax is 25V. What would the BJT parameters and ratings be if both junction areas (AJE
and AJC) are doubled?
(a) β = 604, Imax = 10 A, Vmax = 25 V
(b) β = 302, Imax = 20 mA, Vmax = 25 V
(c) β = 604, Imax = 20 mA, Vmax = 50 V
(d) β = 151, Imax = 10 mA, Vmax = 25 V
(e) β = 302, Imax = 20 mA, Vmax = 12.5 V
(f) β = 604, Imax = 20 mA, Vmax = 25 V

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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An NPN BJT with base-emitter and base-collector junction areas A and Ac respectively has the following parameters: the transport factor a = 0.9999 and the emitter efficiency Ye = 0.9968. The ratings of the transistor are as follows: the maximum collector current Imax is 10 mA, and the maximum collector-base voltage Vmax is 25V. What would the BJT parameters and ratings be if both junction areas A and Ac are doubled? a = 604, Imax = 10 mA, Vmax = 25V.
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Transcript

-
00:01 In this question, it is given that sun is making revolutions around the galaxy and we have given the angular velocity of this sun.
00:11 Now we have to find the time taken by sun to complete one revolution.
00:15 So first of all i am writing the given data for this question.
00:19 We have given the angular velocity of the sun that is 1 .67 into 10 to the power minus 15 radian per second.
00:27 And we have given that it will complete one revolution.
00:30 So theta is equal to one revolutions or i can say that is 2 pi radiance.
00:36 Now we know that time that is delta t is written as theta upon omega.
00:42 So put the value of theta and omega so this is 2 pi upon 1 .67 into 10 to the power minus 15 after solving this we get time in second that is 3 .76 to 3 3 3 to 3 3 into 10 to the power 15 seconds...
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