Let θ be the angle between the vectors u = 2i + 3j - 6k and v = 2i + 3j + 6k. (a) Use the dot product to find cosθ. (b) Use the cross product to find sinθ. (c) Confirm that sin²θ + cos²θ = 1.
Added by Lisa F.
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(a) Use the dot product to find cos?: cos? = (2i+3j?6k)(2i+3j+6k) = 12 Show more…
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