Let (Ω, F, P) be a probability space. Let A, B, D ∈ F be events such that P(A|D) ≥ P(A) and P(B|D) ≥ P(B). Show that if A ∩ B = ∅, then P(Ā ∩ B̄|D) ≤ P(Ā ∩ B̄). Note: Ā represents the complement of event A.
Added by Gui G.
Step 1
We are given that P(A|D) ≥ P(A) and P(B|D) ≥ P(B). This means that the probability of A occurring given D has occurred is greater than or equal to the probability of A occurring, and similarly for B. Show more…
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