We need to find the derivative $f'(x)$. We will use the product rule, which states that if $f(x) = u(x)v(x)$, then $f'(x) = u'(x)v(x) + u(x)v'(x)$.
In our case, let $u(x) = -3x^4$ and $v(x) = \ln x$. Then $u'(x) = -12x^3$ and $v'(x) = \frac{1}{x}$.
Applying the
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