Question

Let $f(x) = -6 - x^2$. Find each of the following: a) \frac{f(-3) - f(-8)}{-3 - (-8)} = 11 b) \frac{f(-8 + h) - f(-8)}{h} = \boxed{} c) \lim_{h \to 0} \frac{f(-8 + h) - f(-8)}{h} = \boxed{}

          Let $f(x) = -6 - x^2$. Find each of the following:
a) \frac{f(-3) - f(-8)}{-3 - (-8)} = 11
b) \frac{f(-8 + h) - f(-8)}{h} = \boxed{}
c) \lim_{h \to 0} \frac{f(-8 + h) - f(-8)}{h} = \boxed{}

Let f(x) = -6 - x^2. Find each of the following:
a) (f(-3) - f(-8))/(-3 - (-8)) = 11
b) (f(-8 + h) - f(-8))/(h) =
c) limh →0 (f(-8 + h) - f(-8))/(h) =

Added by Christopher R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Yujie Wang

01/25/2023

Step 1

f(-3) = -6 - (-3)^2 = -6 - 9 = -15 f(-8) = -6 - (-8)^2 = -6 - 64 = -70 Show more…

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Let f(x)=-6-x^(2). Find each of the following: a) (f(-3)-f(-8))/(-3-(-8))= b) (f(-8+h)-f(-8))/(h)= c) lim_(h->0)(f(-8+h)-f(-8))/(h)= Let f=6-2.Find each of the following: f-3-f-8 a -3--8 f-8+h-f-8 b) h c) lim f-8+h-f-8 04 h