Let $f(x) = \begin{cases} 2.7x + 11.1 & \text{if } x < -3 \\ \sqrt{x+12} & \text{if } x > -3 \\ -2 & \text{if } x = -3 \end{cases}$ Determine which one of the following rules for continuity is violated at $x = -3$. $\lim_{x \to a} f(x) = f(a)$. $\lim_{x \to a} f(x)$ exists. $f(a)$ is defined. None of the above; the function is continuous at $x = -3$. Add Work Submit Question
Added by Jenny G.
Close
Step 1
For a function $f(x)$ to be continuous at a point $x=a$, three conditions must be met: 1. $f(a)$ must be defined. 2. $\lim_{x \to a} f(x)$ must exist. This means that the left-hand limit and the right-hand limit must be equal: $\lim_{x \to a^-} f(x) = \lim_{x \to Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 71 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Let f(x) = { 3.7x + 12.7 if x < -1, sqrt(x + 82) if x > -1, -2 if x = -1. Determine which one of the following rules for continuity is violated at x = -1. f(a) is defined. lim x->a f(x) = f(a). lim x->a f(x) exists. None of the above; the function is continuous at x = -1.
Adi S.
The graph below is the function f(x) Determine which one of the following rules for continuity is violated at x = 2. Select the first rule that is violated. f(a) is defined. lim x->a f(x) exists. lim x->a f(x) = f(a).
The graph below is the function
Hoan N.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD