Question

Let \begin{equation} f(x) = \frac{2\sqrt{x}}{8x^2 + 3x - 12} \end{equation} Evaluate $f'(x)$ at $x = 2$.

          Let \begin{equation*} f(x) = \frac{2\sqrt{x}}{8x^2 + 3x - 12} \end{equation*} Evaluate $f'(x)$ at $x = 2$.

Let
f(x) = (2√(x))/(8x^2 + 3x - 12)
Evaluate f'(x) at x = 2.

Added by Mason A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Dwijendra Rao

10/04/2021

Step 1

Step 1: Find the derivative of $f(x)$ using the quotient rule: $f'(x) = \frac{(8x^2 + 3x - 12)\frac{d}{dx}(2\sqrt{x}) - (2\sqrt{x})\frac{d}{dx}(8x^2 + 3x - 12)}{(8x^2 + 3x - 12)^2}$ Show more…

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Let $f(x) = \frac{2\sqrt{x}}{8x^2 + 3x - 12}$ Evaluate $f'(x)$ at $x = 2$.

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Let \begin{equation*} f(x) = \frac{2\sqrt{x}}{8x^2 + 3x - 12} \end{equation*} Evaluate $f'(x)$ at $x = 2$.

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Let \begin{equation} f(x) = \frac{2\sqrt{x}}{8x^2 + 3x - 12} \end{equation} Evaluate $f'(x)$ at $x = 2$.