Let $f(x) = 4x^4 - 4x^3 - 1$. Find the equation of the line tangent to the graph of $y = f(x)$ at the point $(2, 31)$. \The equation of the tangent line is $y = $
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The derivative of f(x) is f'(x) = 16x^3 - 12x^2. Show more…
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