Let f(x)=(6)/(x).
Then the expression (f(x+h)-f(x))/(h) can be written in the form
(A)/(x(x+h))
where A is a constant and A=
Using your answer from above we have:
f^(')(x)=lim_(h->0)(f(x+h)-f(x))/(h)=
Finally, find each of the following:
f^(')(1)=
f^(')(2)=
f^(')(3)=
6 Let f=
fx+h)-f( Then the expression can be written in the form h
A
x(x+h)'
where A is a constant and A
Using your answer from above we have: f(x+h)-f(x) f')=lim h-0 h
Finally, find each of the following:
f'(1)=
f'2=
f3=