Let R be a commutative ring with unity. Let I and J be ideals of R. Let D = \{x \in R \mid xb \in I \text{ for all } b \in J\}. Prove that D is an ideal of R.
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Since I and J are ideals of R, they contain the zero element of R. Therefore, for any b in J, we have 0*b = 0, which means that 0 is in D. Thus, D is non-empty. Show more…
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