00:01
In the question it is given r is equals to matrix 2, q.
00:06
So r u is equals to a b 0 c where a b and c belongs to q.
00:19
Next we have let a and b belongs to r u.
00:25
So from this we can say a is equals to a 1 b 1 0 c 1 and b is equals to a 2 b 2 0 and c 2.
00:40
Now next we have a 1 minus b 1.
00:44
This will be equals to a 1 minus a 2 b 1 minus b 2 0 and c 1 minus c 2.
00:53
This also belongs to r u as a 1 minus a 2 comma b 1 minus b 2 and c 1 minus c 2 belongs to q.
01:08
So from this we can write next a b will be a 1 b 1 0 c 1 multiplied with a 2 b 2 0 c 2 which gives us the value a 1 a 2 a 1 b 2 plus b 1 c 2 0 and c 1 c 2.
01:33
This is an upper triangular matrix.
01:42
So from this we can write a minus b a b both belongs to r u for a and b belonging to r u.
01:56
Therefore r u is a bring of this is the proof for first part.
02:11
Next we have part b.
02:13
So part b gives us that we have to prove for pi r u belongs to r 1 as follows...