Let $z=f(x-y, y-x) .$ Show that $\partial z / \partial x+\partial z / \partial y=0$.
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Step 1
Using the chain rule, we have: $\frac{\partial z}{\partial x} = \frac{\partial f}{\partial (x-y)} \cdot \frac{\partial (x-y)}{\partial x} + \frac{\partial f}{\partial (y-x)} \cdot \frac{\partial (y-x)}{\partial x}$ $\frac{\partial z}{\partial y} = Show more…
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