\lim_{t \to 0} \sqrt{a - t}
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Then we have $$ L = \lim_{t \to 0} \sqrt{a-t} $$ Since the function $f(t) = \sqrt{a-t}$ is continuous at $t=0$, we can directly substitute $t=0$ into the expression: $$ L = \sqrt{a-0} = \sqrt{a} $$ Thus, the limit is $\sqrt{a}$. Show more…
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