Question

\lim_{x \to -2} \frac{x^3 + 8}{x + 2}

Name: limx →-2 (x^3 + 8)/(x + 2)
Uploaded: 2021-09-24T10:11:11-08:00
Duration: 3 min 53 s
Channel: Yujie Wang
Description: limx →-2 (x^3 + 8)/(x + 2)

          \lim_{x \to -2} \frac{x^3 + 8}{x + 2}

Added by Michael J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Yujie Wang

09/24/2021

Step 1

1 and x = -2.01 using the given function f(x) = (x^3 + 8)/(x + 2). For x = -2.1: f(-2.1) = (-2.1)^3 + 8 / (-2.1 + 2) = (-9.261 + 8) / (-0.1) = -1.261 / -0.1 = 12.61 For x = -2.01: f(-2.01) = (-2.01)^3 + 8 / (-2.01 + 2) = (-8.060301 + 8) / (-0.01) = -0.060301 / Show more…

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lim_(x->-2)(x^(3)+8)/(x+2) Create a table of values for the function. able[[x,-2.1,-2.01],[f(x),,]] Use the table to estimate the limit. Use a gri lim_(x->-2)(x^(3)+8)/(x+2)~~ X3+8 X-2X+2 Create a table of values for the function.Ll X -2.1 2.01 f(x) Use the table to estimate the limit. Use a gr x-2x+2