00:01
In this question, we are asked to determine the values of x and y, satisfying the condition x times y is greater than 0.
00:10
First, let's sketch the xy coordinate system.
00:18
Recall that the first quadrant corresponds to the positive values of x and y.
00:23
In the second quadrant, x becomes negative, y is still positive.
00:28
In the third quadrant, both x and y are negative.
00:31
And in the fourth quadrant, x is positive and y is negative.
00:38
Now, when x and y are both in the first quadrant, we're going to get that we're multiplying two positive numbers because in the first quadrant both x and y are positive, right? so we're going to get that x times y is going to be positive.
01:06
Now, note that in the second quadrant, x is negative and y is positive.
01:14
So if x and y belong to the second quadrant, we are going to get a product of a negative.
01:24
A negative number by a positive number which is going to give us a negative number.
01:33
So x is negative here and y is positive.
01:38
That's why we are getting a negative number...