Question

MULTIPLE CHOICE 1. If 6 m^3 of oil weighs 47 kN, calculate its specific gravity and specific volume. A. SG = 0.80, $V_s$ = 1.25 cm^3/kg B. SG = 0.80, $V_s$ = 0.80 cm^3/kg C. SG = 1.25, $V_s$ = 1.25 cm^3/kg D. SG = 1.25, $V_s$ = 0.80 cm^3/kg

          MULTIPLE CHOICE
1.
If 6 m^3 of oil weighs 47 kN, calculate its specific gravity and specific
volume.
A. SG = 0.80, $V_s$ = 1.25 cm^3/kg
B. SG = 0.80, $V_s$ = 0.80 cm^3/kg
C. SG = 1.25, $V_s$ = 1.25 cm^3/kg
D. SG = 1.25, $V_s$ = 0.80 cm^3/kg

MULTIPLE CHOICE
1.
If 6 m^3 of oil weighs 47 kN, calculate its specific gravity and specific
volume.
A. SG = 0.80, Vs = 1.25 cm^3/kg
B. SG = 0.80, Vs = 0.80 cm^3/kg
C. SG = 1.25, Vs = 1.25 cm^3/kg
D. SG = 1.25, Vs = 0.80 cm^3/kg

Added by Debra V.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

05/01/2023

Step 1

Density = Weight / Volume Density = 47 kN / 6 m^3 Density = 7.83 kN/m^3 Show more…

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MULTIPLE CHOICE If 6m^(^(^()))3 of oil weighs 47kN, calculate its specific gravity and specific volume. A. SG=0.80,V_(S)=1.25cm^(^(^()))(3)/(k)g C. SG=1.25,V_(S)=1.25cm^(^(^()))(3)/(k)g B. SG=0.80,V_(S)=0.80cm^(^(^()))(3)/(k)g D. SG=1.25,V_(S)=0.80cm^(^(^()))(3)/(k)g MULTIPLE CHOICE 1. If 6 m^3 of oil weighs 47 kN, calculate its specific gravity and specific volume. A.SG=0.80,Vs=1.25 cm^3/kg C. SG=1.25Vs=1.25cm^3/kg B. SG=0.80Vs=0.80cm^3/kg D. SG=1.25Vs=0.80 cm^3/kg