Question

E. coli cells are rod-shaped, about 2 µm long and 0.8 µm in diameter. E. coli has a protective cell envelope 10 nm thick. What percentage of the total volume of the bacterium does the cell envelope occupy? E. coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter 18 nm), which carry out protein synthesis. What percentage of the cell volume do the ribosomes occupy? The molecular weight of an E. coli DNA molecule is about $3.1 \times 10^9$ g/mol. The average molecular weight of a nucleotide pair is 660 g/mol, and each nucleotide pair contributes 0.34 nm to the length of DNA. Calculate the length of an E. coli DNA molecule.

          E. coli cells are rod-shaped, about 2 µm long and 0.8 µm in diameter. E. coli has a protective cell envelope 10 nm thick.
What percentage of the total volume of the bacterium does the cell envelope occupy?
E. coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter 18 nm), which carry out protein synthesis.
What percentage of the cell volume do the ribosomes occupy?
The molecular weight of an E. coli DNA molecule is about $3.1 \times 10^9$ g/mol. The average molecular weight of a nucleotide pair is 660 g/mol, and each nucleotide pair contributes 0.34 nm to the length of DNA.
Calculate the length of an E. coli DNA molecule.

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E. coli cells are rod-shaped, about 2 µm long and 0.8 µm in diameter. E. coli has a protective cell envelope 10 nm thick.
What percentage of the total volume of the bacterium does the cell envelope occupy?
E. coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter 18 nm), which carry out protein synthesis.
What percentage of the cell volume do the ribosomes occupy?
The molecular weight of an E. coli DNA molecule is about 3.1 × 10^9 g/mol. The average molecular weight of a nucleotide pair is 660 g/mol, and each nucleotide pair contributes 0.34 nm to the length of DNA.
Calculate the length of an E. coli DNA molecule.

Added by Tiffany A.

Biology for AP Courses

Julianne Zedalis, John Eggebrecht

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Solved by Expert Madhur L

08/30/2023

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coli bacterium as a cylinder with dimensions given: 2 μm long and 0.8 μm in diameter. Show more…

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n 8 of 12 E. coli cells are rod-shaped, about 2mu m long and 0.8mu m in Giameter. E. coli has a protective cell envelope 10nm thick. What percentage of the total volume of the bacterium does the cell envelope occupy? E. coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter 18nm ), which carry out protein synthesis. What percentage of the cell volume do the ribosomes occupy? The molecular weight of an E. coli DNA molecule is about 3.1 imes 10^(9)(g)/(m)ol. The average molecular weight of a nucleotide pair is 660(g)/(m)ol, and each nucleotide pair contributes 0.34nm to the length of DNA. Calculate the length of an E. coli DNA molecule. fraction of the envelope in the total volume: percentage of the ribosomes in the total volume: DNA length: n 8 of12 E.coli cells are rod-shaped.about 2m long and 0.8um in ameter.E.coli has a protective cell envelope 10 nm thick. fraction of the envelope in the total volume: What percentage of the total volume of the bacterium does the cell envelope occupy? Macm E. coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter 18 nm), which carry out protein synthesis. percentage of the ribosomes in the total volume: What percentage of the cell volume do the ribosomes occupy? The molecular weight of an E.coli DNA molecule is about 3.1 10 g/mol.The average molecular weight of a nucleotide pair is 660 g/mol,and each nucleotide pair contributes 0.34 nm to the length of DNA DNA length: Calculate the length of an E.coli DNA molecule

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Transcript

00:01 Hello students, in this question, we are given with different values of the size of a bacterium and we need to find the volume percentage of the envelope from that.

00:10 So, first of all, we find the volume of the bacterium.

00:17 So, here we are given with length of bacterium that's 2 micron, diameter 0 .8 micrometer and length of envelope that is 10 nanometer, which is 0 .01 micrometer.

00:35 Now, we find the volume of with the envelope.

00:43 So, that is equal to total volume or vt.

00:47 Let's use the formula pi r square h, which is since it's a rod shape, so it's a cylinder.

00:54 So, we use the volume formula that will be 3 .14 into 0 .16 into 2 .01 that is 1 .05.

01:13 Now, so this much micrometer.

01:21 Now, the volume of bacteria is again this, we use the same formula.

01:31 So, that is now we find the volume percentage of envelope by subtracting the total volume by the volume of bacteria.

01:40 So, vt minus vb that is 1 .05 minus 1 .004, which is 0 .046.

01:50 Now, to get the proportion, we just multiply, we just divide 0 .046 by the total volume that is 0 .0438, which is equal to 4 .38%.

02:13 In the next one, we tend to find out the proportion of ribosomes inside the bacterium with respect to the total volume of the bacterial cell.

02:23 Now, since we have already calculated the total volume, we now calculate the volume of ribosome.

02:29 So, that will can be written as vr.

02:36 Now, we know that the volume of sphere is 4 by 3 pi r cube into these many ribosome numbers...

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