Naval intelligence reports that 4 enemy vessels in a fleet of 22 are carrying nuclear weapons. If 8 vessels are randomly targeted and destroyed, what is the probability that more than 1 vessel transporting nuclear weapons was destroyed? Express your answer as a fraction or a decimal number rounded to four decimal places.
Added by Amy C.
Step 1
This can be calculated using the combination formula: C(n, r) = n! / (r!(n-r)!), where n is the total number of vessels (22) and r is the number of vessels chosen (8). C(22, 8) = 22! / (8!(22-8)!) = 319770 Show more…
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