Naval intelligence reports that 8 enemy vessels in a fleet of 19 are carrying nuclear weapons. If 6 vessels are randomly targeted and destroyed, what is the probability that more than 1 vessel transporting nuclear weapons was destroyed? Express your answer as a fraction or a decimal number rounded to four decimal places.
Added by Laura B.
Step 1
This can be calculated using combinations, denoted as C(n, k) or "n choose k", where n is the total number of items and k is the number of items to choose. In this case, n = 19 and k = 6. C(19, 6) = 19! / (6! * (19 - 6)!) C(19, 6) = 19! / (6! * 13!) C(19, 6) = Show more…
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