Question

On a certain mountain, the elevation $z$ in miles above a point $(x, y)$ in an $x y$ -plane at sea level is $z=2000-2 x^{2}-4 y^{2}$ ft. The positive $x$ -axis points east, and the positive y-axis north. A climber is at the point (-20,5,1100) (a) If the climber uses a compass reading to walk due west, will she begin to ascend or descend? (b) If the climber uses a compass reading to walk northeast, will she ascend or descend? At what rate? (c) In what compass direction should the climber begin walking to travel a level path (two answers)?

          On a certain mountain, the elevation $z$ in miles above a point $(x, y)$ in an $x y$ -plane at sea level is $z=2000-2 x^{2}-4 y^{2}$ ft. The positive $x$ -axis points east, and the positive y-axis north. A climber is at the point (-20,5,1100)
(a) If the climber uses a compass reading to walk due west, will she begin to ascend or descend?
(b) If the climber uses a compass reading to walk northeast, will she ascend or descend? At what rate?
(c) In what compass direction should the climber begin walking to travel a level path (two answers)?
        
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Added by Samuel W.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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On a certain mountain, the elevation $z$ in miles above a point $(x, y)$ in an $x y$ -plane at sea level is $z=2000-2 x^{2}-4 y^{2}$ ft. The positive $x$ -axis points east, and the positive y-axis north. A climber is at the point (-20,5,1100) (a) If the climber uses a compass reading to walk due west, will she begin to ascend or descend? (b) If the climber uses a compass reading to walk northeast, will she ascend or descend? At what rate? (c) In what compass direction should the climber begin walking to travel a level path (two answers)?
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Transcript

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00:01 Hello students in this question we are given the elevation of a certain mountain.
00:05 This is the point where the climber is currently standing.
00:08 These are the directions given.
00:10 So we have f of xy is equal to 2000 minus 2x2x2x2x2 .2x2 .2x2.
00:20 We have fx x.
00:23 X comma y is equal to minus 4x and fy x.
00:27 X comma y is equal to minus 8y at minus 20 .5 this is 80 and this is minus 40.
00:45 For the a part, the question is asking that whether she is ascending or descending if she is moving towards west.
00:54 So the direction vector for this will be minus icap and so the direction.
01:04 Derivatives is equal to 80 i cap minus 40 jcap dot product with minus i cap this is minus 80 since it is negative so she is descending for the b part we have to find whether she is ascending or descending when she's moving towards northeast direction for this the direct directions are given by vector i cap plus j cap.
01:47 So, directional derivative at minus 20 comma 5 is equal to 80 icap minus 40 j cap...
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