Question

On a number line, explain why $\frac{-1}{100}$ is greater than $\frac{-1}{10}$. Since $\frac{-1}{10} = \frac{-10}{100}$, then $\frac{-10}{100} + \frac{9}{100} = \frac{1}{100}$. Also, since $\frac{9}{100}$ is a negative number then $\frac{-10}{100} > \frac{-1}{100}$. Therefore, $\frac{-1}{100}$ is farther to the left on a number line and greater than $\frac{-1}{10}$

          On a number line, explain why $\frac{-1}{100}$ is greater than $\frac{-1}{10}$.
Since $\frac{-1}{10} = \frac{-10}{100}$, then $\frac{-10}{100} + \frac{9}{100} = \frac{1}{100}$. Also, since $\frac{9}{100}$ is a negative number then $\frac{-10}{100} > \frac{-1}{100}$. Therefore, $\frac{-1}{100}$ is farther to the left on a number line and greater than $\frac{-1}{10}$

On a number line, explain why (-1)/(100) is greater than (-1)/(10).
Since (-1)/(10) = (-10)/(100), then (-10)/(100) + (9)/(100) = (1)/(100). Also, since (9)/(100) is a negative number then (-10)/(100) > (-1)/(100). Therefore, (-1)/(100) is farther to the left on a number line and greater than (-1)/(10)

Added by Tracy P.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Teresa Fuston

01/28/2022

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Step 1: We are asked to explain why $\frac{-1}{100}$ is greater than $\frac{-1}{10}$ on a number line. Show more…

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On a number line, explain why $\frac{-1}{100}$ is greater than $\frac{-1}{10}$. Since $\frac{-1}{10} = \frac{-10}{100}$, then $\frac{-10}{100} + \frac{9}{100} = \frac{1}{100}$. Also, since $\frac{9}{100}$ is a negative number then $\frac{-10}{100} > \frac{-1}{100}$. Therefore, $\frac{-1}{100}$ is farther to the left on a number line and greater than $\frac{-1}{10}$.