Question

P 9.8-20 Find the differential equation for $v_o(t)$ in the circuit of Figure P 9.8-20, using the direct method. Find $v_o(t)$ for time t > 0 for each of the following sets of component values: (a) C = 1 F, L = 0.25 H, $R_1$ = $R_2$ = 1.309 ? (b) C = 1 F, L = 1 H, $R_1$ = 1 ?, $R_2$ = 3 ? (c) C = 0.125 F, L = 0.5 H, $R_1$ = 4 ?, $R_2$ = 1 ? Answer: (a) $v_o(t) = \frac{1}{2} - e^{-2t} + \frac{1}{2}e^{-4t}$ V (b) $v_o(t) = \frac{3}{4} - (\frac{3}{4} + \frac{3}{2}t)e^{-2t}$ V (c) $v_o(t) = 0.2 - e^{-2t}(0.2 \cos 4t + 0.1 \sin 4t)$ V

          P 9.8-20 Find the differential equation for $v_o(t)$ in the circuit
of Figure P 9.8-20, using the direct method. Find $v_o(t)$ for time
t > 0 for each of the following sets of component values:
(a) C = 1 F, L = 0.25 H, $R_1$ = $R_2$ = 1.309 ?
(b) C = 1 F, L = 1 H, $R_1$ = 1 ?, $R_2$ = 3 ?
(c) C = 0.125 F, L = 0.5 H, $R_1$ = 4 ?, $R_2$ = 1 ?
Answer:
(a) $v_o(t) = \frac{1}{2} - e^{-2t} + \frac{1}{2}e^{-4t}$ V
(b) $v_o(t) = \frac{3}{4} - (\frac{3}{4} + \frac{3}{2}t)e^{-2t}$ V
(c) $v_o(t) = 0.2 - e^{-2t}(0.2 \cos 4t + 0.1 \sin 4t)$ V

P 9.8-20 Find the differential equation for vo(t) in the circuit
of Figure P 9.8-20, using the direct method. Find vo(t) for time
t > 0 for each of the following sets of component values:
(a) C = 1 F, L = 0.25 H, R1 = R2 = 1.309 ?
(b) C = 1 F, L = 1 H, R1 = 1 ?, R2 = 3 ?
(c) C = 0.125 F, L = 0.5 H, R1 = 4 ?, R2 = 1 ?
Answer:
(a) vo(t) = (1)/(2) - e^-2t + (1)/(2)e^-4t V
(b) vo(t) = (3)/(4) - ((3)/(4) + (3)/(2)t)e^-2t V
(c) vo(t) = 0.2 - e^-2t(0.2 cos 4t + 0.1 sin 4t) V

Added by Janet W.

Question

Please give Ace some feedback