6. Particle P moves along the x-axis such that, for time t > 0, its position is given by xP(t) = 6 - 4e^(-t).
Particle Q moves along the y-axis such that, for time t > 0, its velocity is given by vQ(t) = 1/t^2.
At time t = 1, the position of particle Q is yQ(1) = 2.
(a) Find vP(t), the velocity of particle P at time t.
(b) Find aQ(t), the acceleration of particle Q at time t. Find all times t, for t > 0, when the speed of particle Q is decreasing. Justify your answer.
(c) Find yQ(t), the position of particle Q at time t.
(d) As t approaches infinity, which particle will eventually be farther from the origin? Give a reason for your answer.