Question

An object moves along a coordinate line with acceleration $a(t) = (t+2)^3$ units per second per second. The initial velocity is 9 units per second. The velocity function is $v(t) =$ The initial position is 3 units to the right of the origin. The position function is $s(t) = $

          An object moves along a coordinate line with acceleration $a(t) = (t+2)^3$ units per second per second.
The initial velocity is 9 units per second.
The velocity function is $v(t) =$
The initial position is 3 units to the right of the origin.
The position function is $s(t) = $

An object moves along a coordinate line with acceleration a(t) = (t+2)^3 units per second per second.
The initial velocity is 9 units per second.
The velocity function is v(t) =
The initial position is 3 units to the right of the origin.
The position function is s(t) =

Added by Ashley F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Noble

09/03/2023

Step 1

To find the velocity function, we need to integrate the acceleration function with respect to time. v(t) = ∫a(t) dt v(t) = ∫(t+2)^3 dt v(t) = ∫(t^3 + 6t^2 + 12t + 8) dt v(t) = (1/4)t^4 + 2t^3 + 6t^2 + 8t + C Given that the initial velocity is 9 units per second, Show more…

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Please help! I leave good reviewsAn object moves along a coordinate line with acceleration a(t)=(t+2)^(3) units per second per second. The initial velocity is 9 units per second. The velocity function is v(t)= The initial position is 3 units to the right of the origin. The position function is s(t)= An object moves along a coordinate line with acceleration a(t) (t + 2) units per second per second The initial velocity is 9 units per second The velocity function is (t) The initial position is 3 units to the right of the origin The position function is s(t)=