Let \(\varphi : G \to G'\) be a homomorphism of groups and let \(H\) be a subgroup of \(G\). Show that \(H \ker \varphi = \varphi^{-1}(\varphi(H))\).
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Hker is the set of elements in G that map to the identity element of the codomain under the homomorphism G. In other words, Hker = {g ∈ G | φ(g) = e}, where φ is the homomorphism and e is the identity element of the codomain. -1H is the set of elements obtained Show more…
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