Question

Find the velocity and acceleration vectors in terms of $u_r$ and $u_\theta$. $r = a(7 - \sin \theta)$ and $\frac{d\theta}{dt} = 3$, where a is a constant $v = (-3a \cos \theta) u_r + (21a - 3a \sin \theta) u_\theta$ $a = (9a(2 \sin \theta - 7)) u_r + (-18a \cos \theta) u_\theta$

          Find the velocity and acceleration vectors in terms of $u_r$ and $u_\theta$.
$r = a(7 - \sin \theta)$ and $\frac{d\theta}{dt} = 3$, where a is a constant
$v = (-3a \cos \theta) u_r + (21a - 3a \sin \theta) u_\theta$
$a = (9a(2 \sin \theta - 7)) u_r + (-18a \cos \theta) u_\theta$

Find the velocity and acceleration vectors in terms of ur and uθ.
r = a(7 - sinθ) and (dθ)/(dt) = 3, where a is a constant
v = (-3a cosθ) ur + (21a - 3a sinθ) uθ
a = (9a(2 sinθ - 7)) ur + (-18a cosθ) uθ

Added by Iker S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Melissa Munoz

Step 1

We are given that v = (-3acosÎ¸)ur + (21a - 3asinÎ¸)ue. Since Î¸ = 3, we can substitute this value into the equation to get v = (-3acos3)ur + (21a - 3asin3)ue. Simplifying further, we have v = (-3acos3)ur + (21a - 3asin3)ue. Show more…

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Find the velocity and acceleration vectors in terms of ur and ue. Given r = a(7 - sin Î¸) and Î¸ = 3, where a is a constant dt, v = (-3acosÎ¸)ur + (21a - 3asinÎ¸)ue a = 9a(2sinÎ¸ - 7)ur + (-18acosÎ¸)ue