Question

28. In a sequence, the first term, $a_1$, is between 0 and 1. For all $n \ge 1$, $a_{2n} = a_2 \cdot a_n + 1$ and $a_{2n+1} = a_2 \cdot a_n - 2$. Given that $a_7 = 2$, what is the value of $a_2$?

          28. In a sequence, the first term, $a_1$, is between 0 and 1.
For all $n \ge 1$, $a_{2n} = a_2 \cdot a_n + 1$ and $a_{2n+1} = a_2 \cdot a_n - 2$.
Given that $a_7 = 2$, what is the value of $a_2$?

28. In a sequence, the first term, a1, is between 0 and 1.
For all n ≥ 1, a2n = a2 · an + 1 and a2n+1 = a2 · an - 2.
Given that a7 = 2, what is the value of a2?

Added by William M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Naresh Bagrecha

Step 1

We need to find the value of a^2. To find a^2, we can substitute the value of a into the equation a^2n = a(a + 1). So, a^2n = 2(2 + 1) = 2(3) = 6. Show more…

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XCODE I Kangaroo Mathematics Competition 2022 Student Level (Grades 11-12) 2-30 71:17 28. In a sequence, the first term, a, is between 0 and 1. For all n â‰¥ 1, a2n = a(a + 1) and a2n+1 = a2(a - 2). Given that a = 2, what is the value of a2? 5 POINTS A) 1 B) 2 C) 3 D) 4 E) 5 O: 10%