PROBLEM 2.93 Knowing that, for the plate shown, the allowable stress is 125 MPa, determine the maximum allowable value of P when (a) r = 12 mm, (b) r = 18 mm. SOLUTION A = (60)(15) = 900 mm^2 = 900 x 10^-6 m^2 D/d = 120 mm / 60 mm = 2.00 (a) r = 12 mm r/d = 12 mm / 60 mm = 0.2 From Fig. 2.60b, K = 1.92 ?_max = K * P/A P = (A * ?_max) / K = (900 x 10^-6)(125 x 10^6) / 1.92 = 58.6 x 10^3 N = 58.3 kN (b) r = 18 mm, r/d = 18 mm / 60 mm = 0.30 From Fig 2.60b, K = 1.75 P = (A * ?_max) / K = (900 x 10^-6)(125 x 10^6) / 1.75 = 64.3 x 10^3 N = 64.3 kN
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The allowable stress is given as 125 MPa. The problem is divided into two parts: (a) when the radius (r) is 12 mm, and (b) when the radius (r) is 18 mm. Show more…
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