Ethane at 25°C and 1.1 atm (abs) flowing at a rate of 100...

Ethane at 25°C and 1.1 atm (abs) flowing at a rate of 100 mol/s is burned with 20% excess oxygen at 175 °C and 1.1 atm (abs). The combustion products ($C_2H_6$, $O_2$, $N_2$, CO, $CO_2$, $H_2O$), leave the furnace at 800°C and 1 atm. a) What is the volumetric flow rate of oxygen (L/s) fed to the furnace? b) What should the volumetric flow rate of the combustion products be if there are no ethane and carbon monoxide in the product stream? State all assumptions you make.

Transcript

00:01 Hello students, welcome here in this question we have ethane combustion.

00:05 So ethane at combustion.

00:09 So here it is, the temperature is given 25 degrees celsius and pressure is 1 .1 atmosphere.

00:18 So flowing at the rate of 100 moles per second and is burned with 20 % excess of oxygen.

00:30 Excess oxygen at 175 degrees celsius and the 1 .1 atmospheres we have so oxygen is at 175 degrees celsius and 1 .1 atmospheric pressure and the combustion products leave so for products products of combustion are leaving at the temperature 800 degrees celsius and the pressure is one atmosphere.

01:08 So here the question is we need to find out the volumetric flow rate.

01:15 Flow rate, that is volumetric flow rate.

01:22 Fluoride of oxygen fed to the furnace.

01:33 Furness.

01:34 And the second question is we need to find out the same volumetric flow rate for products.

01:41 Okay so we need to find out these two things so we will see the first thing so first thing is ethane which is c2 h4 c2 h6 is reacting with o2 to give uh c o2 plus h2 so if you balance this one so this is two most and this one is seven most and this one is four most and this one is six so for 1 mole of c 1 mole we need 3 .5 more of o2 and it is for 2 most of co2 will produce and here it is 3 most of h2o will produce for 1 more of methane methane.

02:27 So we will see the amount of hydrogen that is equal to so amount of oxygen required.

02:38 So flow rate is given 100 mole per second is given.

02:41 So then it must be 350 mole per second.

02:47 But we have 20 % excess.

02:52 So 20 % excess means excess means what is this? so 350 plus 350 multiplied by 0 .2.

03:05 Then it is equal to 420 we can say.

03:12 Here it is the excess of total oxygen rate is moles per second we are using.

03:20 Now the flow rate of oxygen we need to find out at the temperature.

03:28 So volumetric flow rate, flow rate of oxygen we need to find out.

03:40 So that is equal to from pv is equal to nrt.

03:45 So v is equal to v.

03:48 We need to know.

03:50 So this is the moles per second we have n and r is equal to 0 .08 to 1...

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