Question

4. Find $\frac{dy}{dt}$ for $y = e^{cos^2(\pi t - 10)}$. Choose the correct derivative of the function. A. $\frac{dy}{dt} = -2\pi cos(\pi t - 10)sin(\pi t - 10)e^{cos^2(\pi t - 10)}$ B. $\frac{dy}{dt} = \pi sin^2(\pi t - 10)e^{cos^2(\pi t - 10)}$ C. $\frac{dy}{dt} = \pi cos(\pi t - 10)sin(\pi t - 10)e^{cos^2(\pi t - 10)}$ D. $\frac{dy}{dt} = -2\pi sin^2(\pi t - 10)e^{cos^2(\pi t - 10)}$

          4.
Find $\frac{dy}{dt}$ for $y = e^{cos^2(\pi t - 10)}$.
Choose the correct derivative of the function.
A. $\frac{dy}{dt} = -2\pi cos(\pi t - 10)sin(\pi t - 10)e^{cos^2(\pi t - 10)}$
B. $\frac{dy}{dt} = \pi sin^2(\pi t - 10)e^{cos^2(\pi t - 10)}$
C. $\frac{dy}{dt} = \pi cos(\pi t - 10)sin(\pi t - 10)e^{cos^2(\pi t - 10)}$
D. $\frac{dy}{dt} = -2\pi sin^2(\pi t - 10)e^{cos^2(\pi t - 10)}$

4.
Find (dy)/(dt) for y = e^cos^2(π t - 10).
Choose the correct derivative of the function.
A. (dy)/(dt) = -2π cos(π t - 10)sin(π t - 10)e^cos^2(π t - 10)
B. (dy)/(dt) = π sin^2(π t - 10)e^cos^2(π t - 10)
C. (dy)/(dt) = π cos(π t - 10)sin(π t - 10)e^cos^2(π t - 10)
D. (dy)/(dt) = -2π sin^2(π t - 10)e^cos^2(π t - 10)

Added by Rachel S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

06/03/2022

Step 1

Let u = rt-10, then du = rdt. Show more…

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Please show the steps on how A is right. 4 Find for y = ecos(rt-10) dt Choose the correct derivative of the function: A. dt B. dy = sin(rt-10)ecos(xt-10) C. dy/dp D. dy = -2rsin(rt-10)ecos(xt-10) dt