For the following function, find the value of (a) f(-2) and (b) f(1), if possible. $\begin{aligned} y = \begin{cases} x^2 - 5 & \text{if } x \le 0\\ x^3 + 2 & \text{if } x > 0 \end{cases} \end{aligned}$ (a) Select the correct choice below and, if necessary, fill in the answer box to complete your answer.
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Since f(x) is defined differently for x ≤ 0 and x > 0, we need to consider both cases. For x ≤ 0, we have f(x) = KK 2 - 5. So, af-2 = KK 2 - 5. For x > 0, we have f(x) = x^3 + 2. So, af-2 = (-2)^3 + 2 = 8 + 2 = 10. Show more…
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