Question

Molarity of H2SO3 Stock solution 0.01 M Total volume of reaction 100 mL Mixture mL used Initial concentration [H2SO3] (M) ln [H2SO3] 1/[H2SO3] Time required 1 10 0.001 -6.91 1000 227 sec 2 20 0.002 -6.21 500 92 sec 3 30 0.003 -5.81 333 61 sec

          Molarity of H2SO3 Stock solution 0.01 M Total volume of reaction 100 mL
Mixture mL used Initial concentration [H2SO3] (M) ln [H2SO3] 1/[H2SO3] Time required
1 10 0.001 -6.91 1000 227 sec
2 20 0.002 -6.21 500 92 sec
3 30 0.003 -5.81 333 61 sec

Molarity of H2SO3 Stock solution 0.01 M Total volume of reaction 100 mL
Mixture mL used Initial concentration [H2SO3] (M) ln [H2SO3] 1/[H2SO3] Time required
1 10 0.001 -6.91 1000 227 sec
2 20 0.002 -6.21 500 92 sec
3 30 0.003 -5.81 333 61 sec

Added by Crystal B.

Chemistry: An Atoms-Focused Approach

Thomas R. Gilbert, Rein V. Kirss,… 2nd Edition

Chapter 8

Instant Answer

Solved by Expert Jean Gephart

03/02/2024

Step 1

If the plot is a straight line, it indicates a first order reaction. Second, if it is a first order reaction, the rate law is Rate = k[H2SO3], where k is the rate constant. Third, to find the value of k, we can use the slope of the straight line in the plot. Show more…

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Plot of ln[H2SO3] VERSUS time. Does this graph establish the order reaction? If it does, what is the rate law in respect to [H2SO3] and what is k for this reaction?