00:02
All right, so this problem gives us this curve here, and we want to find the slope of a tangent line at the point 1 -1.
00:09
So to do that, we're going to need to use implicit differentiation.
00:14
So we're going to take the derivative of both sides with respect to x.
00:17
So we'll have 2x for the first part.
00:19
Now, this quotient here is going to need quotient rule.
00:23
So we have our bottom function times the derivative of the top, minus top function, derivative of the bottom.
00:31
There's our y prime all over the bottom function squared.
00:36
We have another quotient rule.
00:38
So we have bottom function derivative of the top minus top function derivative of the bottom, all over bottom function squared.
00:50
And we also have the plus one, but that doesn't do anything for the derivative.
00:58
Okay.
00:59
So now what we need to do is algebraically solve for.
01:03
Y prime.
01:04
You can do this a whole bunch of different ways.
01:07
I would prefer to clear the denominators.
01:09
So i'm going to multiply every single term by both x squared and y squared...