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(1 point) Find bases for the column space, the row space, and the null space of matrix A. You should verify that the Rank-Nullity Theorem holds. An equivalent echelon form of matrix A is given to make your work easier.\ $A = egin{bmatrix} 4 & 16 & 3\ 3 & 1 & 0\ -6 & -3 & 5\ 2 & 6 & -2\ -6 & 10 & 6 end{bmatrix} sim egin{bmatrix} 1 & 0 & 0\ 0 & 1 & 0\ 0 & 0 & 1\ 0 & 0 & 0\ 0 & 0 & 0 end{bmatrix}$\Basis for the column space of A is\${\\}$\Basis for the row space of A is\${\\}$\Note that since the only solution to $Ax = mathbf{0}$ is the zero vector, there is no basis for the null space of A.

          (1 point) Find bases for the column space, the row space, and the null space of matrix A. You should verify that the Rank-Nullity Theorem holds. An equivalent echelon form of matrix A is given to make your work easier.\
$A = egin{bmatrix} 4 & 16 & 3\ 3 & 1 & 0\ -6 & -3 & 5\ 2 & 6 & -2\ -6 & 10 & 6 end{bmatrix} sim egin{bmatrix} 1 & 0 & 0\ 0 & 1 & 0\ 0 & 0 & 1\ 0 & 0 & 0\ 0 & 0 & 0 end{bmatrix}$\Basis for the column space of A is\${\\}$\Basis for the row space of A is\${\\}$\Note that since the only solution to $Ax = mathbf{0}$ is the zero vector, there is no basis for the null space of A.

(1 point) Find bases for the column space, the row space, and the null space of matrix A. You should verify that the Rank-Nullity Theorem holds. An equivalent echelon form of matrix A is given to make your work easier.A = eginbmatrix 4 16 3 3 1 0 -6 -3 5 2 6 -2 -6 10 6 endbmatrix sim eginbmatrix 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 endbmatrixfor the column space of A is$
for the row space of A is$that since the only solution to Ax = mathbf0 is the zero vector, there is no basis for the null space of A.

Added by Mohamed C.

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