00:01
Hello everyone, here we have to find the equation of parabola in the format y equal to a x square plus b.
00:14
So, they have given the vertices of the triangle 1 comma 0, 2 comma 2 and 3 comma 4 and also they have given s is equal to a plus b the whole square plus 4 a plus b minus 2 the whole square plus 9 a plus b minus 4 the whole square.
00:35
So, we have to frame the equation of parabola.
00:38
So, first we partial derivative with respect to a that is dou s by dou a will gives you 2 into a plus b plus 2 into 4 a plus b minus 2 into 4 plus 2 into 9 a plus b minus 4 into 9.
01:01
So, this gives you 2 a plus 2 b plus 8 into 4 a plus b minus 2 plus 18 into 9 a plus b minus 4.
01:15
So, solving this we will be getting 196 a plus 28 b minus 88 equal to 0.
01:24
So, further i am equating another thing after partial derivative we should equate dou s by dou a equal to 0.
01:32
So, again i have reduced into lowest term i will be getting 49 a plus 7 b minus 22 equal to 0.
01:42
So, that is dou s by dou a i have got 49 a plus 7 b minus 22 equal to 0.
01:49
Similarly, next we have to find dou s by dou b...