Question

The form of the partial fraction decomposition of a rational function is given below. frac{x - x^2 - 13}{(x - 4)(x^2 + 9)} = frac{A}{x - 4} + frac{Bx + C}{x^2 + 9} A = -1 B = 0 C = 1 Now evaluate the indefinite integral. int frac{x - x^2 - 13}{(x - 4)(x^2 + 9)} dx = -ln(x-4)+(1/3)arctan((1/3)x)+C

          The form of the partial fraction decomposition of a rational function is given below.

frac{x - x^2 - 13}{(x - 4)(x^2 + 9)} = frac{A}{x - 4} + frac{Bx + C}{x^2 + 9}

A = -1 B = 0 C = 1

Now evaluate the indefinite integral.

int frac{x - x^2 - 13}{(x - 4)(x^2 + 9)} dx = -ln(x-4)+(1/3)arctan((1/3)x)+C

$The form of the partial fraction decomposition of a rational function is given below. fracx - x^2 - 13(x - 4)(x^2 + 9) = fracAx - 4 + fracBx + Cx^2 + 9 A = -1 B = 0 C = 1 Now evaluate the indefinite integral. int fracx - x^2 - 13(x - 4)(x^2 + 9) dx = -ln(x-4)+(1/3)arctan((1/3)x)+C$