Question

(1 point) To solve the separable differential equation 6yy' = x we must find two separate integrals: ? dy = and ? dx = Solving for y we get two solutions, one positive y = and one negative y = (Note: you must simplify all arbitrary constants down to one constant k) Find the particular solution satisfying the initial condition y(0) = 1. y(x) =

          (1 point) To solve the separable differential equation
6yy' = x
we must find two separate integrals:
? dy =
and
? dx =
Solving for y we get two solutions, one positive
y = and one negative
y = (Note: you must
simplify all arbitrary constants down to one
constant k)
Find the particular solution satisfying the initial
condition
y(0) = 1.
y(x) =

(1 point) To solve the separable differential equation
6yy' = x
we must find two separate integrals:
? dy =
and
? dx =
Solving for y we get two solutions, one positive
y = and one negative
y = (Note: you must
simplify all arbitrary constants down to one
constant k)
Find the particular solution satisfying the initial
condition
y(0) = 1.
y(x) =

Added by Hugo J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

02/04/2023

Step 1

dy = 6yy - 1 We can integrate this equation using the substitution y = kx to get dy = 6kx - 1 We can also use the chain rule to get dy = 6kx - k We can combine these two equations to get dy = 6kx - 6 Show more…

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To solve the separable differential equation 6yy' = x we must find two separate integrals: ∫ dy = and ∫ dx = Solving for y we get two solutions, one positive y = and one negative y = (Note: you must simplify all arbitrary constants down to one constant k) Find the particular solution satisfying the initial condition y(0) = 1. y(x) =