Let $f(x) = ax + b$. Compute, in terms of $a$ and $b$, the derivatives of (i) arcsin[$f(x)$]: (ii) arccos[$f(x)$]: (iii) arctan[$f(x)$]:
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**Step 2:** For the first part, we need to find the derivative of \(\arcsin[f(2)] = \arcsin(ax + b)\). **Step 3:** The derivative of \(\arcsin x\) is \(\frac{1}{\sqrt{1-x^2}}\). Applying this to our function, we get: \[\frac{d}{dx}(\arcsin(ax + b)) = Show more…
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