Problem 4: A hollow shaft having an internal diameter 40% of its external diameter, transmits 562.5 kW power at 100 r.p.m. Determine the external diameter of the shaft if the shear stress is not to exceed 60 N/mm² and the twist in a length of 2.5m should not exceed 1.3 degrees. Assume maximum torque = 1.25 mean torque and modulus of rigidity = 9*10? N/mm².
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Power (P) = 562.5 kW = 562500 W Speed (N) = 100 rpm We know that P = (2 * π * N * Tm) / 60 So, Tm = (P * 60) / (2 * π * N) Tm = (562500 * 60) / (2 * π * 100) Tm = 53696.48 Nmm Show more…
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